Here's the follow up post to Schur's Lemma, in case you were anxiously awaiting it.
The corollary says that if α=β, f has to be a multiple of the identity function (or unit matrix).
For the proof one looks at an eigenvalue λi. And subtracts the following on both sides:
This changes to:
Now we apply the Schur's Lemma from last time and find out that has to be either invertible or the 0 function. But it cannot be invertible because λi is an eigenvalue (actually the only eigenvalue). And we have what we wanted.
A Defense of Journal Impact Factors - Vilified, journal impact factor may still be useful for scientists. But use it with caution.
9 hours ago